Question

Find three consecutive integers whose sum is −96.

Answer 1

The first consecutive integer = - 33

The second consecutive integer = - 32

The third consecutive integer = - 31

Explanation:

So since the three numbers are consecutive we can make the following equation. If we let "n: be the value of the first consecutive integer, the value of the second consecutive integer would be "n + 1" and the value of the third one would be "n + 2". So the equation we can write is...

n + (n + 1) + (n + 2) = - 96

3n + 3 = - 96

3n = - 99

n = - 33

Therefor:

The first consecutive integer = n = - 33

The second consecutive integer = n + 1 = - 33 + 1 = - 32

The third consecutive integer = n + 2 = - 33 + 2 = - 31

Answer 2

Answer:Let 2n + 4 = the third consecutive even number. Therefore, the three consecutive even numbers whose sum is 96 are indeed 30, 32, and 34.

Explanation: