Question

What is the height of a right triangle with an angle that measures 60 degrees and a base of 18.

Answer 1

Given the question in the question tab, the following are the solution steps to get the height of the triangle.

Step 1: Draw the triangle

Step 2: State the known parameters

`\begin{gathered} \text{base}=\text{adjacent}=18 \\ height=\text{opposite}=x=\text{?} \\ \text{angle}=60^(\circ) \end{gathered}`

Step 3: Write the formula for finding x

`\tan x=\frac{\text{opposite}}{\text{adjacent}}`

Step 4: Find the height of the triangle (x)

`\begin{gathered} \tan 60=(x)/(18) \\ By\text{ cross multiplication}, \\ x=18* tan60 \\ x=31.17691454 \\ x=31.177\text{ to 3 decimal places.} \end{gathered}`

Hence, the height of the right angled triangle is 31.177 approximately to three decimal places