Question

The length of a rectangle is one unit shorter than one-sixth of the width, x.

Enter an expression in the box that represents the perimeter of the rectangle.

Note: Use one variable and a fraction in the answer.

Answer 1

P = 2(L + W)

L = 1/6W - 1

P = 2(1/6W - 1 + W)
P = 2(7/6W - 1)
P = 7/3W - 2......oh, w is supposed to be x....7/3x - 2....I know u want a variable and a fraction...but I got a constant in there

Answer 2

Let

y--------> the length of the rectangle

x--------> the width of the rectangle

we know that

The perimeter of the rectangle is equal to

`P=2x+2y` -------> equation
`1`

`y=(1)/(6)x-1` --------> equation
`2`

Substitute equation
`2` in equation
`1`

`P=2x+2*[(1)/(6)x-1]\\ \\P=2x+(2)/(6)x-2\\ \\P=(14)/(6)x-2\\ \\P=((7)/(3)x-2)\ units`

therefore

the answer is

the perimeter of the rectangle is

`P=((7)/(3)x-2)\ units`