Question

Suppose a population is carrying a condition controlled by two alleles: R (dominant) and r (recessive). If the frequency of the r allele is 15%, and the frequency of the R allele is 85%, what will be the frequency of the RR genotype, assuming evolution is not occurring?

A. 25.5 percent
B. 72.25 percent
C. 12.75 percent
D. 2.25 percent

Answer 1

B.) 72.25 percent.

Hopefully this helps! =^ ^=

Answer 2

Since no evolution is happening we can use the Hardy-Weinberg equation to solve this problem. This equation enables us to calculate the frequency of a genotype from the frequencies of the alleles.

`R^(2)` the frequency of the dominant homozygote

2Rr the frequency of the heterozygote

`r^(2)` the frequency of the recessive homozygote

Therefore, the frequency of the RR genotype is R
`^(2)` = 0,85[tex] ^{2} which is 0,72.