Question

Marcus is buying 10 gift bags for his birthday party. He will choose items to put in the bags and then pay an additional charge of $0.75 for the actual bag. Marcus cannot spend more than $50. Write and solve an inequality to find the most Marcus can spend on the items for each bag.

Answer 1

Since they do not specify that the items are equal lets assume that a b c d e f g h i j represent the cost of the items in the 10 gift bags.
10 x 0.75=7.50
thus
(7.50-7.50+a+b+c+d+e+f+g+h+i+j)< or = 50 - 7.50
a+b+c+d+e+f+g+h+i+j < or = $42.50

Answer 2

Answer with Step-by-step explanation:

Let cost of items for 10 bags be represented by x

Cost of 1 bag=$ 0.75

Cost of 10 bags=$ (0.75×10)

= $ 7.5

Total cost of 10 bags with items in them=$(7.5+x)

Marcus cannot spend more than $50.

i.e. 7.5+x≤50

Subtracting both sides by 7.5

x≤42.5

Most Marcus can spend for items in 10 bags=$42.5

Most Marcus can spend for items in 1 bag=$(42.5/10)=$4.25

Hence, most Marcus can spend on the items for each bag is:

$4.25