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Solve y^2 + 4y - 32 = 0 using the zero product property.

A. y=3
B. y = -8, 4
C. y = 8, -4
D. y = -8, 6

1 Answer

3 votes
Hello,

y²+4y-32=0
<==>y²+8y-4y-32=0
<==>y(y+8)-4(y+8)=0
<==>(y+8)(y-4)=0
<==> y=-8 or y=4
Sol={-8;4}
Answer A

User Ritesh Choudhary
by
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