Question

Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of –0.1 m/s. What is the resulting velocity of marble B after the collision?

Answer 1

the other ball will move with speed 0.96 m/s

Step-by-step explanation:

Here in collision type of questions we can use momentum conservation because there is no force on the system

So here we will have

`m_a v_(1i) + m_b v_(2i) = m_a v_(1f) + m_b v_(2f)`

so here we have

`0.08(0.5) + 0.05(0) = 0.08(-0.1) + 0.05 v`

`0.048 = 0.05 v`

`v = 0.96 m/s`

So the light ball will move with speed 0.96 m/s

Answer 2

The resulting velocity of marble B after the collision is 0.96 m/s.

Step-by-step explanation:

Mass of marble A ,
`m_1= 0.08 kg`

Initial velocity of the marble A,
`u_1 = 0.5 m/s`

Mass of marble B,
`m_2 = 0.05 kg`

Initial velocity of the marble B,
`u_2 = 0 m/s`

final velocity of the marble A,
`v_1 = -0.1 m/s`

final velocity of the marble B,
`v_2 = ?`

Applying law of conservation of mass:

`m_1u_1+m_2u_2=m_1v_1+m_2v_2`

`0.08 kg* 0.5 m/s+0.05kg* 0 m/s=0.08 kg* (-0.1 m/s)+0.05kg * v_2`

`v_2=0.96 /s`

The resulting velocity of marble B after the collision is 0.96 m/s.