Question

I don't really understand. Worth 12 points!

Heat = mass(m) * specific heat capacity(c) * temp. change(delta T)

ITEMBANK:
a.) 1.04kJ
b.) 10.4 kJ
c.) 14.5 kJ
d.) 44.8 kJ

Match each item from the item bank to its corresponding match:

1.)Heat = mass * c * temp change
175g 0.79J/gC 75 C

2.)Heat = mass * c * temp change
352g 1.65J/gC 25 C

3.)Heat = mass * c * temp change
268g 4.18J/gC 40 C

4.)Heat = mass * c * temp change
74g 0.21J/gC 67 C


I don't have to have the answer to all of them; i just need help understanding what to do.

Answer 1

Answer: 1 → b

2 → c

3 → d

d → a

Step-by-step explanation

`Q=mc\Delta T`

1000 J = 1 kJ

1.) m = 175 g, c = 0.79 J/g °C, ΔT = 75°C

`Q=175g* 0.79J/g^oC* 75^oC=10,368.75 J=10.368 kJ\approx 10.4 kJ`

2.) m = 352 g, c = 1.65 J/g °C, ΔT = 25°C

`Q=352g* 1.65J/g^oC* 25^oC=14,520 J=14.520 kJ`

3. m = 268 g, c = 4.18 J/g °C, ΔT = 40°C

`Q=268g* 4.18J/g^oC* 40^oC=44,809.6J=44.809 kJ`

4. m = 74 g, c = 0.21 J/g °C, ΔT = 67°C

`Q=74g* 0.21J/g^oC* 67^oC=1,041.18 J=1.041 kJ`

Answer 2

1.)Heat = mass * c * temp change
Heat = 175g x 0.79J/gC x 75 C = 10368.75 J
b.) 10.4 kJ

2.)Heat = mass * c * temp change
Heat = 352g x 1.65J/gC x 25 C = 14520 J
c.) 14.5 kJ

3.)Heat = mass * c * temp change
Heat = 268g x 4.18J/gC x 40 C = 44809.6 J
d.) 44.8 kJ

4.)Heat = mass * c * temp change
Heat = 74g x 0.21J/gC x 67 C = 1041.18 J
a.) 1.04kJ