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Please help me create a truth table for the statement p^(qv~p)
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Please help me create a truth table for the statement p^(qv~p)
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Jun 12, 2017
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Please help me create a truth table for the statement p^(qv~p)
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Nightfirecat
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Hello,
1) p∧(q∨¬p)=(p∧q)∨(p∧¬p)=p∧q proof:
2)
p|q|¬p|q∨¬p|p∧(q∨¬p)|p∧q
0|0|..1|.......1|..............0|0
0|1|..1|.......1|..............0|0
1|0|..0|.......0|..............0|0
1|1|..0|.......1|..............1|1
Signus
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Jun 16, 2017
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Signus
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