Answer:
a = -4 or 3
Explanation:
(x, y) therefore, with (a, 12) x = a and y = 12
y = x^2 + x
12 = a^2 + a
a^2 + a - 12 = 0 (quadratic equation)
a^2 + 4a - 3a - 12 = 0
a(a+4) - 3(a+4)
(a + 4) (a - 3) = 0
a = -4, 3
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