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Did either student verify the identity property? Explain why or why not. Name 2 identities that were used in student A's verification and the steps they appear in.

Did either student verify the identity property? Explain why or why not. Name 2 identities-example-1
User Roman Kotov
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1 Answer

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Solution:

The question is given below as


cotx(cosx)=cscx-sinx

Step 1:

We will make use of the quotient identity below


cotx=(cosx)/(sinx)
\begin{gathered} cotx(cosx)=cscx-s\imaginaryI nx \\ (cosx)/(sinx)(cosx)=cscx-s\mathrm{i}nx \\ (cos^2x)/(sinx)=cscx-s\mathrm{i}nx \end{gathered}

Step 2:

We will make use of the Pythagorean identity below


\begin{gathered} cos^2x+sin^2x=1 \\ cos^2x=1-sin^2x \end{gathered}
\begin{gathered} (cos^(2)x)/(s\imaginaryI nx)=cscx-s\imaginaryI nx \\ (1-sin^2x)/(sinx)=cscx-s\mathrm{i}nx \\ (1)/(sinx)-(sin^2x)/(sinx)=cscx-s\mathrm{i}nx \\ cscx-sinx=cscx-s\mathrm{i}nx(PROVED) \end{gathered}

Hence,

STUDENT A and STUDENT B both proved it properly,

STUDENT A proved it from left to right

STUDENT B proved it from right to left

For STUDENT A's work,

Quotient identity was used in step 1


cotx=(cosx)/(sinx)

Pythagorean identity was used in step 3


\begin{gathered} cos^2x+sin^2x=1 \\ cos^2x=1-sin^2x \end{gathered}

Reciprocal identity was used in step 5


cscx=(1)/(sinx)

User Crag
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