Question

The specific heat of copper is 0.092 cal/g °C. If a 590 g copper pan is heated from a temperature of 25 °C to 180 °C, how many calories of heat energy will the copper pan absorb?

Answer 1

`Q=cm \Delta T\\\\ c=0,092(cal)/(g^(o)C)\\ m=590g\\ \Delta T=180^(o)C-25^(o)C=155^(o)C\\\\ Q=0,092(cal)/(g^(o)C)*590g*155^(o)C=8413,4cal`