area equal 99 in square and given that the length of rectangle is 2 in longer than the width so l = w+2
l*w=99
(w+2)*w = 99
w^2 +2w =99
w^2 +2w -99 = 0
D = 4 -4*(-99) = 4+396 = 400
w_1,2 = (-2+/- sqrt400)/2 = (-2+/- 20)/2
w_1,2 = -11 and 9
so bc. a length not can being minus so this mean that the width of the rectangle is equal 9 in so choice c. is right sure
hope helped