Final answer:
The point (-3, 2) must be on the graph of an even function if the point (3, 2) is on it, due to the symmetric property of even functions about the y-axis.
Step-by-step explanation:
An even function is symmetric about the y-axis, meaning if a point (a, b) is on the graph, then the point (-a, b) must also be on the graph. In the case of the point (3, 2) being on the graph of an even function, the other point that must also be on the graph is (-3, 2). This symmetry is because, for even functions, the relationship y(x) = y(-x) holds. Therefore, since (3, 2) is a point on the function, reflecting this point across the y-axis would result in the point (-3, 2), which will also lie on the graph of the function. This is a fundamental property of even functions and is a helpful characteristic in determining the behaviour of these functions graphically.