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Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.


A(n)=5+(n-1)( (1)/(6) )

three answers

User Joddy
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2 Answers

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A(1)=5+(1-1)((1)/(6))=5+0((1)/(6))=5+0=5

A(14)=5+(5-1)((1)/(6))=5+4((1)/(6))=5+(4)/(6)=5(2)/(3)

A(10)=5+(10-1)((1)/(6))=5+9((1)/(6))=5+(9)/(6)=6(1)/(2)
User Serge Tarkovski
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Answer:

The first term is
A(1)=5

The fourth term is
A(4)=(11)/(2).

The tenth term is
A(10)=(13)/(2)

Explanation:

Given : Arithmetic sequence
A(n)=5+(n-1)( (1)/(6) )

To find : The first, fourth, and tenth terms of the arithmetic sequence described by the given rule?

Solution :

Arithmetic sequence
A(n)=5+(n-1)((1)/(6))

Substitute, n=1,4,10 to find the given terms

Put n=1,


A(1)=5+(1-1)((1)/(6))


A(1)=5+(0)((1)/(6))


A(1)=5

The first term is
A(1)=5

Put n=4,


A(4)=5+(4-1)((1)/(6))


A(4)=5+(3)((1)/(6))


A(4)=5+(1)/(2)


A(4)=(11)/(2)

The fourth term is
A(4)=(11)/(2).

Put n=10,


A(10)=5+(10-1)((1)/(6))


A(10)=5+(9)((1)/(6))


A(10)=5+(3)/(2)


A(10)=(13)/(2)

The tenth term is
A(10)=(13)/(2)

User Alexandre Abreu
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