Answer
P2 = 9.218 atm
Step-by-step explanation
Given:
Initial temperature (T1) = 66 °C = 339 K
Final temperature (T2) = 352 °C = 625 K
Initial pressure (P1) = 5 atm
Required: Final pressure (P2)
Solution
To solve this problem we will use Gay-Lussac's Law
P1/T1 = P2/T2
we want to solve for P2
P2 = P1T2/T1
P2 = (5 atm x 625 K)/339K
P2 = 9.218 atm