Question

In an experiment 150.0 grams of AsF3 were reacted with 180.0 g of CCl4 to produce AsCl3 and CCl2F2. The theoretical yield of CCl2F2, in grams, is

a)141.5 grams
b)206.2 grams
c)137.5 grams
d)104.4 grams
e)152.6 grams

Answer 1

AsF₃:

M=132g/mol
m=150g

n = m/M = 150g/132g/mol = 1,14mol

CCl₄:

M=154g/mol
m=180g

n = m/M = 180g/154g/mol = 1,17mol

2AsF₃ + 3CCl₄ ⇒ 2AsCl₃ + 3CCl₂F₂
2mol : 3mol : 3mol
1,14mol : 1,17mol : 1,17mol
limiting reagent
0,78mol will react

CCl₂F₂:

n = 1,17mol
M = 121g/mol

m = nM = 1,17mol * 121g/mol = 141,57g

Answer a