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Factor the expression: 7x(x^2-1)-3(x^2-1)

1 Answer

8 votes

Answer:

x = 1

Explanation:

The factors of the given expression is as follows:


7x(x^2-1) -3(x^2-1)\\\\7x^3 - 7x - 3x^2 +3\\\\7x^3 - 3x^2 -7x + 3

If we considered x = 1

So

7 - 3 -7 + 3 = 0

0 = 0

Hence, the factor would be x = 1

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