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Find the constant of variation for the quadratic variation.

9y = 4x2

A) -2
B) 4/9
C) 2/3
D) 9/4

User Hrust
by
8.1k points

2 Answers

4 votes

Answer:

option B is correct

The constant of variation is,
k=(4)/(9).

Explanation:

Since the quadratic variation is the relationship between the variables x and y

i.e,
y=kx^2; where k is the quadratic variation.

Given quadratic equation:
9y=4x^2 ...[1]

Division property of equality states that you divide the same number to both sides of an equation

Divide both side by 9,we get


(9y)/(9)= (4)/(9)x^2

On simplifying we get;


y= (4)/(9)x^2

Now, compare above equation by equation[1] we get the value of k;

i.e,
k=(4)/(9)

Therefore, the constant of variation is,
k=(4)/(9).

User SarekOfVulcan
by
7.6k points
3 votes
we are given the equation 9y = 4x2 and is asked in teh problem the constant of variation for the quadratic equation. In this case, the standard form is y = kx2 where k is the constant of variation. Hence we divide the equation by 9 such that k is equal to 4/9
User Remmyabhavan
by
8.5k points

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