Question

Graph a line that contains the point 1 (4,3) and has a slope of 2 y 6- 4- 2 х -6 -4 2 4 6 -4 -6

Answer 1

To solve the exercise you can use the point-slope formula, that is,

`\begin{gathered} y-y_1=m(x-x_1) \\ \text{ Where m is the slope of the line and} \\ (x_1,y_1)\text{ is a point through which the line passes} \end{gathered}`

So, in this case, you have

`\begin{gathered} m=(1)/(2) \\ (x_1,y_1)=(4,3) \end{gathered}`
`\begin{gathered} y-y_1=m(x-x_1) \\ \text{ Replace} \\ y-3=(1)/(2)(x-4) \\ y-3=(1)/(2)x-(1)/(2)\cdot4 \\ y-3=(1)/(2)x-2 \\ \text{ Add 3 from both sides of the equation} \\ y-3+3=(1)/(2)x-2+3 \\ y=(1)/(2)x+1 \end{gathered}`

Then,