Question

Quadrilateral ABCD has coordinates A (3, -5), B (5, -2), C (10, -4), D (8, -7). Quadrilateral ABCD is a

AB = sqr root (5-3)^2 + (-2+5)^2 = sqr root 13
BC = sqr root(10-5)^2 + (-4+2)^2= sqr root 29
CD= sqr root(8-10)^2 + ((-7+4)^2 = sqr root 13
DA = sqr root(3-8)^2 + (-5+7)^2 = sqr root 29

Answer 1

we are given the coordinates of a quadrilateral. IN this case, we are asked in the problem to determine the length of the sides. Through the distance formula square root of [(x2-x1)^2 + (y2-y1)]^2. in this case, there are two congruent sides opposite to each other. This quadrilateral could be a parallelogram.