Question

An automobile engineer is revising a design for a conical chamber that was originally specified to be 12 inches long with a circular base diameter of 5.7 inches. In the new design, the chamber is scaled by a factor of 1.5. What is the volume of the revised chamber? Round your answer to two decimal places.

Answer 1

The volume of the cylinder is:
V= pi* (r^2) * h.

So the volume is = pi * (5.7/2)^2 * 12 = 306.2 in^2.
Since it is scaled up by the factor of 1.5, so we have to multiply each dimension with 1.5.
That means the diameter will be 8.55 and the height will be 18. so the scaled up volume will be

=pi * ((5.7*1.5)/2)^2 * (12*1.5)

The answer then would have to be 1033.5