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Write an equation of a line that passes through (-1,3)and (1,4)

User Jon Edmiston
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SOLUTION

We want to write an equation of a line that passes through (-1,3) and (1,4)

First, let us find the slope m of the line for the points (-1,3) and (1,4)

We have


\begin{gathered} m=(4-3)/(1-(-1)) \\ m=(1)/(1+1) \\ m=(1)/(2) \end{gathered}

Now, equation of a line in point slope form becomes


\begin{gathered} y-y_1=m(x-x_1) \\ (x_1,y_1)=(-1,3) \end{gathered}

plugging in the values, we have


\begin{gathered} y-y_1=m(x-x_1) \\ y-3=(1)/(2)(x-(-1) \\ y-3=(1)/(2)(x+1) \\ y-3=(1)/(2)x+(1)/(2) \\ y=(1)/(2)x+(1)/(2)+3 \\ y=(1)/(2)x+(7)/(2) \end{gathered}

Hence the answer becomes


y=(1)/(2)x+(7)/(2)

User Gordon Linoff
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