Question

In a pet store, there are 8 puppies, 10 kittens and 6 parakeets. If a pet is chosen at random, what is the probability of choosing a puppy or a kitten?1234144

Answer 1

FORMULAS

If A and B are any events then:

`P\mleft(AorB\mright)=P\mleft(A\mright)+P\mleft(B\mright)-P\mleft(AandB\mright)`

If A and B are mutually exclusive events then P(A and B) = 0, so then:

`P\mleft(A\text{ }or\text{ }B\mright)=P\mleft(A\mright)+P\mleft(B\mright)`

The probability of an event happening is given to be:

`P=\frac{\text{Number of required events}}{Number\text{ of total events}}`

SOLUTION STEPS

The total number of pets in the store is calculated to be:

`Total=8+10+6=24`

The probability of picking a puppy is:

`P(p)=(8)/(24)`

The probability of picking a kitten is:

`P(k)=(10)/(24)`

Therefore, the probability of choosing a puppy or a kitten is gotten to be:

`P(p\text{ }or\text{ }k)=(8)/(24)+(10)/(24)=(18)/(24)=(3)/(4)`

ANSWER

The probability is 3/4 or 0.75.