we are given the equation 27 x3 + 125 = 0 and is asked in the problem the value of x. In this case, the equation is expressed as 27x3 = -125; x1 = -5/3; x2 =(-15-√-675)/18=(-5-5i√ 3 )/6= -0.8333-1.4434i ; x3 =(-15+√-675)/18=(-5+5i√ 3 )/6= -0.8333+1.4434i