Question

One number is 77 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 883​, find the numbers

Answer 1

x = first number = 9.91
77x = second number = 763.07
x + 100 = third number = 109.91
x + 77x + x + 100 = 883
79x + 100 = 883
-100 -100
79x = 783
/79 /79
x = 9.91 (rounded to nearest hundreth)

77(9.91) = 763.07

9.91 + 100 = 109.91