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The temperature at 8:00 a.m. was –6°F. By 4:00 p.m. the temperature was 17°F. What was the change in temperature from 8:00 a.m. to 4:00 p.m.?

2 Answers

3 votes
It went up 23 Fahrenheit
User Leolo
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6.2k points
4 votes

Answer:


23^(\circ)F

Explanation:

We have been given that the temperature at 8:00 a.m. was –6°F. By 4:00 p.m. the temperature was 17°F. We are asked to find the change in temperature from 8:00 a.m. to 4:00 p.m.

The change in temperature would be final temperature minus initial temperature.


\text{The change in temperature}=17^(\circ)F-(-6^(\circ)F)


\text{The change in temperature}=17^(\circ)F+6^(\circ)F


\text{The change in temperature}=23^(\circ)F

Therefore, the change in temperature from 8:00 a.m. to 4:00 p.m. is 23 degree Fahrenheit.

User Diyism
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7.8k points