Question

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 84 m 6u*o_{1} and 62 m wide.Find the area of the training field. Use the value 3.14 for it, and do not round your answer. Be sure to include the correct unit in your answer.

Answer 1

Step-by-step explanation:

We are given a field made up of a rectangle and two semi circles.

Please take note that two semi-circles with the same diameter can be joined together and we'll have a whole circle.

In other words, this field is made up of

(1) A rectangle

(2) A circle

The dimensions of both shapes are;

`\begin{gathered} Rectangle: \\ l=84m,w=62m \end{gathered}`
`\begin{gathered} Circle: \\ diameter=62m \\ radius=(diameter)/(2)=31m \end{gathered}`

We shall now calculate the area of each after which we will add up our results;

`\begin{gathered} Rectangle: \\ Area=l* w \end{gathered}`
`Area=84*62`
`Area=5208m^2`
`\begin{gathered} Circle: \\ Area=\pi r^2 \end{gathered}`
`Area=3.14*31^2`
`Area=3.14*961`
`Area=3017.54m^2`

We have the area of the rectangular portion of the field, and that of both semi-circles (that is, area of the circle).

We now have the area of the entire field as follows;

`Area=Rectangle+Circle`
`Area=5208+3017.54`
`Area=8225.54m^2`

ANSWER:

`Area=8,225.54m^2`