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If x=6 and y=2 then what is the value of 3x^2-4(2y-4/12)+8​

User Tolluy
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1 Answer

13 votes

Answer:

304/3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Explanation:

Step 1: Define

3x² - 4(2y - 4/12) + 8

x = 6, y = 2

Step 2: Evaluate

  1. Substitute in variables: 3(6)² - 4(2(2) - 4/12) + 8
  2. Evaluate exponents: 3(36) - 4(2(2) - 4/12) + 8
  3. Multiply: 108 - 4(2(2) - 4/12) + 8
  4. (Parenthesis) Multiply: 108 - 4(4 - 4/12) + 8
  5. (Parenthesis - Fraction) Simplify: 108 - 4(4 - 1/3) + 8
  6. (Parenthesis) Subtract: 108 - 4(11/3) + 8
  7. Multiply: 108 - 44/3 + 8
  8. Subtract: 280/3 + 8
  9. Add: 304/3
User Evi
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