1. Identify the given and do necessary conversions:
• Moles of Sodium = 0.1 mol
• volume of sodium hydroxide NaOH= 100cm3 /1000 = 0.1dm^3
• Balanced equation : 2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)
2. Determine mole ratio fro the balanced equation:
2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g
2 : 2 :2 :1
0.1 mol 0.1mol
• We can see that 0.1 mol of Na react with 0.1 mol of water to form 0.1mol NaOH
3. Calculate the concentration of NaOH:
since we have moles n = 0.1 mol
and Volume (v) = 0.1dm^3
Concentration = moles /volume
=0.1mol/0.1dm^3
= 1 mol/dm^3
Therefore , concentration of NaOH = 1mol/dm^3