Question

X-3 and x-1/3 are factors of ax^2+5x+b,show that a=-3/2

Answer 1

Hello,


`ax^2+5x+b=a(x^2+ (5)/(a)*x+ (b)/(a))\\ =k(x-3)(x- (1)/(3))\\ =k(x^2-3x- (1)/(3)*x+1)\\ =k(x^2- (10)/(3)*x+1)\\ x^2--\ \textgreater \ k=a\\ x--\ \textgreater \ 5=-a* (10)/(3) ==\ \textgreater \ a=- (3)/(2) \\ x^0--\ \textgreater \ b=a`