Question

find the slope of f(x)=x^3-2x^2-1 at the point (2,-1). then write the equation of the tangent line at the point (2,-1). show all work

Answer 1

Hello,


`y=x^3-2x^2-1\\ y'=3x^2-4x\ if\ x=2\ then\ y'=3*2^2-4*2=12-8=4\\ The \ equation \ is \ : y+1=4(x-2)\\ y=4x-9`