A motorcycle stunt driver zooms off the end of a cliff at a speed of 30 meters per second. If he lands after 0.75 seconds, what is the height of the cliff?

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asked Dec 16, 2015 61.4k views

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A motorcycle stunt driver zooms off the end of a cliff at a speed of 30 meters per second. If he lands after 0.75 seconds, what is the height of the cliff?

Physics
high-school

Martin Sustrik asked

by Martin Sustrik

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$u = 30ms^(-1) \\t = 0.75s \\a = 9.8ms^(-2) (Gravity) \\s = ?$

$s = ut + (1)/(2)at^2 \\s = (30)(0.75)+ (1)/(2)(9.8)(0.75)^2 \\s = 22.5 + 2.75625 \\s = 25.25625$

s = 25.3 m (3 sf)

Lukewarm answered Dec 20, 2015

by Lukewarm

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