Ethylene glycol (antifreeze) has a density of 1.11 g/cm3. What is the mass in grams of 387 mL of ethylene glycol?

asked Aug 10, 2017 53.8k views

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$d= 1,11(g)/(cm^(3))\\ V=387ml=387cm^(3)\\\\ m=d*V \ \ \ \ \Rightarrow \ \ \ \ m = 1,11(g)/(cm^(3))*387cm^(3)=429,57g$

Ninesalt answered Aug 15, 2017

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