Question

What volume of lead (of density 11.3 g/cm3 ) has the same mass as 395 cm3 of a piece of redwood (of density 0.38 g/cm3 )? Answer in units of cm3 .

Answer 1

`d_(1)=(m)/(V_(1))\\\\ V_(1)=395cm^(3)\\ d_(1)=0,38(g)/(cm^(3)) \ \ \ \ \Rightarrow \ \ \ \ m=395cm^(3)*0,38(g)/(cm^(3))=150,1g\\\\\\ d_(2)=(m)/(V_(2))\\\\ m=150,1g\\ d_(2)=11,3(g)/(cm^(3)) \ \ \ \ \Rightarrow \ \ \ \ V_(2)=(150,1g)/(11,3(g)/(cm^(3)))\approx13,28cm^(3)`