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Solve for the variable: 3(q-5)=2(q+5)
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Solve for the variable: 3(q-5)=2(q+5)

User Jeff Blankenburg
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a(b+c)=ab+ac or
a(b-c)=ab-ac

so

3(q-5)=3q-15
2(q+5)=2q+10

3q-15=2q+10
minus 2q from both sides
q-15=10
add 15 to both sides
q=25
User Asleep
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