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Calculate the wavelength of a photon having energy of 1.257 X 10-24 joules. (Planck’s constant is 6.626 x 10-34 joule seconds; the speed of light is 2.998 x 108 m/s)

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E=h\\u\\\\ \\u=(c)/(\lambda) \ \ \ \Rightarrow E=\frac{hc}\lambda}\\\\ \lambda=(hc)/(E)=(6,626*10^(-34)Js*2,998*10^(8)(m)/(s))/(1,257*10^(-24)J)=15,803*10^{(-34+8)/(-24)}m=\\\\\\=15,803*10^(-2)m=1,5803*10^(-1)m
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