Question

Line AB contains points A (−1, 3) and B (5, 3). Line AB has a slope that is

Answer 1

slope between 2 points, (x1,y1) and (x2,y2) is
slope=(y2-y1)/(x2-x1)

(-1,3) and (5,3)
x1=-1
y1=3
x2=5
y2=3

slope=(3-3)/(5-(-1))=0/(5+1)=0/6=0

slope is 0

Answer 2

Slope of AB is 0.

Explanation:

We have been given a line AB that has A(-1,3) and B(5,3)

We have a formula for slopw:

`Slope=(y_2-y_1)/(x_2-x_1)`

Here,
`x_1=-1,x_2=5,y_1=3,y_2=3`

On substituting the values in the formula we get:

`slope=(3-3)/(5-(-1))`

`\Rightarrow slope=(0)/(6)`

`\Rightarrow slope=0`

Hence, the required slope is: 0.