Question

what is the volume of a sample of helium that has a mass of 6 × 10−3 g, and a density of 0.17847 g/l? answer in units of ml

Answer 1

`d=0,17847(g)/(L)=0,17847(g)/(1000mL)=1,7847*10^(-4)(g)/(mL)\\\\ m = 6*10^(-3)g\\\\\\ V=(m)/(d)=(6*10^(-3)g)/(1,7847*10^(-4)(g)/(mL))\approx3,362*10^1L=33,62mL`