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Find the derivative of ln(cosx²).​

User Blundin
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1 Answer

6 votes

Answer:


\displaystyle (dy)/(dx) = -2x \tan (x^2)

General Formulas and Concepts:

Calculus

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
\displaystyle (d)/(dx)[f(g(x))] =f'(g(x)) \cdot g'(x)

Explanation:

Step 1: Define

Identify


\displaystyle y = \ln (\cos x^2)

Step 2: Differentiate

  1. Logarithmic Differentiation [Derivative Rule - Chain Rule]:
    \displaystyle y' = ((\cos x^2)')/(\cos x^2)
  2. Trigonometric Differentiation [Derivative Rule - Chain Rule]:
    \displaystyle y' = (-\sin x^2 (x^2)')/(\cos x^2)
  3. Basic Power Rule:
    \displaystyle y' = (-2x \sin x^2)/(\cos x^2)
  4. Rewrite [Trigonometric Identities]:
    \displaystyle y' = -2x \tan (x^2)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

User Suhailvs
by
5.5k points
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