Question

Problem 1 The BasketballLet’s assume a basketball is dropped from a height of 1.5 m. How long will it take the basketball to reach the ground and what velocity will it reach?Show Your Problem Solving Steps: Show these below:1) (Simple) Sketch2) Choose origin and coordinate direction.3) Inventory – What is known? [Note: Any variables are now taken with respect to your coordinate system – consider this when you write down values and signs.]4) Write the appropriate kinematics equation(s) and solve.Problem 2 More BasketballsUse these values of initial position and initial velocity in the following questions.Initial position: ___1.0___ m above groundInitial velocity: ___6.3 __ m/s, upQuestion: What is the magnitude and direction of the acceleration as the ball goes up?What is the magnitude and direction of the acceleration as the ball goes down?

Answer 1

1) and 2)

Let's sketch the problem and define the coordinate direction:

3)

We know that the height of the ball is 1.5 meters and its initial velocity is zero.

4)

We can write the following equation for the height of the ball h over the time t:

`\begin{gathered} h=h_0+v_0t+(at^2)/(2) \\ h=1.5+0\cdot t+\frac{(-9.8)t^2_{}}{2} \\ h=1.5-4.9t^2 \end{gathered}`

Problem 2.

The acceleration acting on the ball when it goes up is the gravity acceleration.

Its magnitude is equal to 9.8 m/s² and the direction is down (negative y)

The acceleration acting on the ball when it goes down is the same (gravity acceleration: 9.8 m/s² down), since there is no external force acting on the ball.