Question

What is the vertex of the graph of y = –x2?

(–1, 0)

(0, –1)

(0, 0)

(1, 1)

Answer 1

the vertex of that quadratic is (0,0)

Answer 2

Option (3) is correct.

The vertex of given equation
`y=-x^2` is (0,0)

Explanation:

Given equation
`y=-x^2`

We have to find the vertex of the graph of given equation.

Consider the equation
`y=-x^2`

Since, given equation is a form of quadratic equation
`ax^2+bx+c` with a =-1 , b=c=0, then ,

If the quadratic is written in the form
`y = a(x-h)^2 + k` then the vertex is the point (h, k).

Writing the given equation in the form of
`y = a(x-h)^2 + k` , we get,

`y=-x^2 \Rightarrow y=-(x-0)^2+0`

On comparing, we get,

h = k= 0 and a = -1

Thus, the vertex is (0 , 0)

Option (3) is correct.

The vertex of given equation
`y=-x^2` is (0,0)