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Graph using the slope intercept formula5y-15=-3x

User FryHard
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The slope intercept formula is given by the expression below:


y=mx+b

Where "m" is the slope and b is the y-intercept of the graph.

The first step to solve this problem is to rewrite the given expression in it's slope-intercept form. This is done below:


\begin{gathered} 5y-15=-3x \\ 5y-15+15=-3x+15 \\ 5y=-3x+15 \\ (5y)/(5)=(-3x)/(5)+(15)/(5) \\ y=-(3x)/(5)+3 \end{gathered}

From the expression we know that the y-intercept is "3". We need another point to graph the equation correctly. To find it we will make y=0 and find the value of x.


\begin{gathered} 0=-(3x)/(5)+3 \\ (3)/(5)x=3 \\ 3x=15 \\ x=(15)/(3) \\ x=5 \end{gathered}

We can finally graph the equation. It crosses the y-axis at "3" and the x-axis at "5".

Graph using the slope intercept formula5y-15=-3x-example-1