The empirical formula : Fe₂O₃
Further explanation
Given
34.97g of Iron
15.03g of Oxygen
Required
The empirical formula
Solution
Mol ratio :
Fe(Iron) : 34.97 g : 56 g/mol = 0.624
O(Oxygen) : 15.03 g : 16 g/mol = 0.939
Divide by 0.624 :
Fe : O = 1 : 1.5
Fe : O = 2 : 3