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(a+b+c)-a3-b3-c3=3 (a+b)(b+c)(c+a)
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(a+b+c)-a3-b3-c3=3 (a+b)(b+c)(c+a)
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Apr 12, 2017
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(a+b+c)-a3-b3-c3=3 (a+b)(b+c)(c+a)
Mathematics
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Nominal Animal
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Please find attached photograph for your answer
Adam Ware
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Apr 13, 2017
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Adam Ware
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1.a3,b3 and c3 must be 2 digit number.
2. a3 must be greater than all the other number.
examples: a3-b3-c3=93-83-73
a3-b3-c3=43-33-23
Elesin Olalekan Fuad
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Apr 17, 2017
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Elesin Olalekan Fuad
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