Question

6. Solve the system of equations algebraically. t x - 5y = 6 3x + 4y = 18 I In which quadrant does the solution fall? Quadrant:

Answer 1

`\begin{gathered} x-5y=6\text{ (1)} \\ 3x+4y=18\text{ (2)} \end{gathered}`

From (1) let's solve for x:

`\begin{gathered} \text{Add 5y to both sides:} \\ x=6+5y\text{ (3)} \end{gathered}`

Replace (3) into (2):

`\begin{gathered} 3(6+5y)+4y=18 \\ 18+15y+4y=18 \\ \text{Subtract 18 from boths sides:} \\ 19y=0 \\ y=0 \end{gathered}`

Replace the value of y into (3):

x = 6 + 5(0) = 6 + 0

Therefore, the solution is:

x=6 , y = 0

The solution fall in the first quadrant (I quadrant)