Question

I need help solving this equation using this function: h(r)= √4-r

Answer 1

Given the following function:

`h(r)=√(4-r)`

We will find the value of (r) when 3h(r)+2=4

So, we can write the following equation:

`3√(4-r)+2=4`

We will solve the equation as follows:

1) subtract 2 from both sides

`\begin{gathered} 3√(4-r)+2-2=4-2 \\ 3√(4-r)=2 \end{gathered}`

2) Divide both sides by 3

`√(4-r)=(2)/(3)`

3) Square both sides to eliminate the square root.

`\begin{gathered} 4-r=((2)/(3))^2 \\ \\ 4-r=(4)/(9) \end{gathered}`

4) Combine the like terms

`\begin{gathered} r=4-(4)/(9) \\ \\ r=(32)/(9) \end{gathered}`

So, the answer will be r = 32/9