Question

Mr. Rodriguez invests half his money in land, a tenth in stocks, and. A twentieth in bonds. He puts the remaining $35,000 in his saving account. What is the total amount of money that Mr. Rodriguez saves and invests.

Answer 1

1/2- 10/20
1/10- 2/20
1/20- 1/20
So $35,000 is 7/20 of his money
Then divide 35000/(7/20) to get 100,000 as what he saves

Answer 2

Mr. Rodriguez saves and invests $65,000.

Explanation:

Let Mr. Rodriguez has total money = $x

Now his investment in land =
`(x)/(2)`

Investment in stocks =
`(x)/(10)`

Investment in bonds =
`(x)/(20)`

So total investment =
`(x)/(2)`+
`(x)/(10)`+
`(x)/(20)`

=
`(10x+2x+x)/(20)`

=
`(13x)/(20)`

Remaining amount after investment is $35,000

So 35,000 = x -
`(13x)/(20)`

35,000 =
`(20x-13x)/(20)`

7x = 20 × 35,000

7x = 700,000

x =
`(700,000)/(7)`

x = $100,000

and investments =
`(13x)/(20)` =
`(13*100,000)/(20)` = $65,000

Total amount of money that Mr. Rodriguez saves $65,000.