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Math help pleaseeeeeeeeeeeee. solving the triangle side values not in degree form

Math help pleaseeeeeeeeeeeee. solving the triangle side values not in degree form-example-1
User Nicola Leoni
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1 Answer

23 votes
23 votes

Solution:

Given;


C=90^o,A=52^o,b=219m

Thus;

We would apply the tangent ratio given as;


\begin{gathered} \tan\theta=(opposite)/(adjacent) \\ \\ \tan52^o=(BC)/(219) \\ \\ BC=219\tan52^o \\ \\ BC=280.3m \end{gathered}

Also;


\begin{gathered} \cos\theta=(adjacent)/(hypotenuse) \\ \\ \cos52^o=(219)/(AB) \\ \\ AB=(219)/(\cos52^o) \\ \\ AB=355.7m \end{gathered}

Math help pleaseeeeeeeeeeeee. solving the triangle side values not in degree form-example-1
User Kartik Ayyar
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2.9k points