142k views
5 votes
write the equation of the line that is perpendicular for the line 4x-3y=0 and contains th e point (3,-8)

User Cupitor
by
8.0k points

2 Answers

3 votes
4x - 3y = 0
-3y = -4x
y = (-4/-3)x
y = 4/3x....so ur slope is 4/3....a perpendicular line will have a negative reciprocal slope...all that means is " flip " ur slope and change the sign...so the slope we need is -3/4 (see how I flipped the slope and changed the sign)

y = mx + b
slope(m) = -3/4
(3,-8)...x = 3 and y = -8
now we sub and solve for b, the y intercept
-8 = -3/4(3) + b
-8 = -9/4 + b
-8 + 9/4 = b
- 32/4 + 9/4 = b
- 23/4 = b

so ur perpendicular equation is : y = -3/4x - 23/4
User Dan Gamble
by
8.6k points
3 votes

Answer:

Explanation:

User Eyal Perry
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories